3/2b-5/b=4/7

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Solution for 3/2b-5/b=4/7 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

(3/2)*b-(5/b) = 4/7 // - 4/7

(3/2)*b-(5/b)-(4/7) = 0

(3/2)*b-5*b^-1-4/7 = 0

3/2*b^1-5*b^-1-4/7*b^0 = 0

(3/2*b^2-4/7*b^1-5*b^0)/(b^1) = 0 // * b^2

b^1*(3/2*b^2-4/7*b^1-5*b^0) = 0

b^1

(3/2)*b^2+(-4/7)*b-5 = 0

(3/2)*b^2+(-4/7)*b-5 = 0

DELTA = (-4/7)^2-(-5*4*(3/2))

DELTA = 1486/49

DELTA > 0

b = ((1486/49)^(1/2)-(-4/7))/(2*(3/2)) or b = (-(-4/7)-(1486/49)^(1/2))/(2*(3/2))

b = ((1486/49)^(1/2)+4/7)/3 or b = (4/7-(1486/49)^(1/2))/3

b in { (4/7-(1486/49)^(1/2))/3, ((1486/49)^(1/2)+4/7)/3} 

b in { (4/7-(1486/49)^(1/2))/3, ((1486/49)^(1/2)+4/7)/3 }

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