3/2c+23=3

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Solution for 3/2c+23=3 equation: 



3/2c+23=3

We move all terms to the left:

3/2c+23-(3)=0



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



We add all the numbers together, and all the variables

3/2c+20=0

We multiply all the terms by the denominator


20*2c+3=0

Wy multiply elements

40c+3=0

We move all terms containing c to the left, all other terms to the right

40c=-3

c=-3/40

c=-3/40

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