3/2c+4=1/2c+13

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Solution for 3/2c+4=1/2c+13 equation: 



3/2c+4=1/2c+13

We move all terms to the left:

3/2c+4-(1/2c+13)=0



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R





Domain of the equation: 2c+13)!=0

c∈R



We get rid of parentheses

3/2c-1/2c-13+4=0

We multiply all the terms by the denominator


-13*2c+4*2c+3-1=0

We add all the numbers together, and all the variables

-13*2c+4*2c+2=0

Wy multiply elements

-26c+8c+2=0

We add all the numbers together, and all the variables

-18c+2=0

We move all terms containing c to the left, all other terms to the right

-18c=-2

c=-2/-18

c=1/9

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