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3/2m+1/5m=2
We move all terms to the left:
3/2m+1/5m-(2)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 5m!=0We calculate fractions
m!=0/5
m!=0
m∈R
15m/10m^2+2m/10m^2-2=0
We multiply all the terms by the denominator
15m+2m-2*10m^2=0
We add all the numbers together, and all the variables
17m-2*10m^2=0
Wy multiply elements
-20m^2+17m=0
a = -20; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-20)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:m_{1}=\frac{-b-\sqrt{\Delta}}{2a}m_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{289}=17m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-20}=\frac{-34}{-40} =17/20m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-20}=\frac{0}{-40} =0
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