3/2m-16+m-2/4m-32=m-8/4m

Solution for 3/2m-16+m-2/4m-32=m-8/4m equation:

3/2m-16+m-2/4m-32=m-8/4m

We move all terms to the left:

3/2m-16+m-2/4m-32-(m-8/4m)=0


Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

3/2m+m-2/4m-(+m-8/4m)-16-32=0

We add all the numbers together, and all the variables

m+3/2m-2/4m-(+m-8/4m)-48=0

We get rid of parentheses

m+3/2m-2/4m-m+8/4m-48=0

We calculate fractions


m-m+12m/8m^2+(16m-2)/8m^2-48=0

We add all the numbers together, and all the variables

12m/8m^2+(16m-2)/8m^2-48=0

We multiply all the terms by the denominator


12m+(16m-2)-48*8m^2=0

Wy multiply elements

-384m^2+12m+(16m-2)=0

We get rid of parentheses

-384m^2+12m+16m-2=0

We add all the numbers together, and all the variables

-384m^2+28m-2=0

a = -384; b = 28; c = -2;
Δ = b2-4ac
Δ = 282-4·(-384)·(-2)
Δ = -2288
Delta is less than zero, so there is no solution for the equation