3/2u-4=3-9/u

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Solution for 3/2u-4=3-9/u equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(3/2)*u-4 = 3-(9/u) // - 3-(9/u)

(3/2)*u+9/u-4-3 = 0

3/2*u^1+9*u^-1-7*u^0 = 0

(3/2*u^2-7*u^1+9*u^0)/(u^1) = 0 // * u^2

u^1*(3/2*u^2-7*u^1+9*u^0) = 0

u^1

(3/2)*u^2-7*u+9 = 0

(3/2)*u^2-7*u+9 = 0

DELTA = (-7)^2-(4*9*(3/2))

DELTA = -5

DELTA < 0

u in { } 

u belongs to the empty set

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