3/2x+1/3x+39=105

Solution for 3/2x+1/3x+39=105 equation:

3/2x+1/3x+39=105

We move all terms to the left:

3/2x+1/3x+39-(105)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x+1/3x-66=0

We calculate fractions


9x/6x^2+2x/6x^2-66=0

We multiply all the terms by the denominator


9x+2x-66*6x^2=0

We add all the numbers together, and all the variables

11x-66*6x^2=0

Wy multiply elements

-396x^2+11x=0

a = -396; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-396)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-396}=\frac{-22}{-792}
=1/36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-396}=\frac{0}{-792}
=0
$