3/2x+1/5x=17

Solution for 3/2x+1/5x=17 equation:

3/2x+1/5x=17

We move all terms to the left:

3/2x+1/5x-(17)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We calculate fractions


15x/10x^2+2x/10x^2-17=0

We multiply all the terms by the denominator


15x+2x-17*10x^2=0

We add all the numbers together, and all the variables

17x-17*10x^2=0

Wy multiply elements

-170x^2+17x=0

a = -170; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-170)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-170}=\frac{-34}{-340}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-170}=\frac{0}{-340}
=0
$