3/2x+20=2(x-16)

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Solution for 3/2x+20=2(x-16) equation: 



3/2x+20=2(x-16)

We move all terms to the left:

3/2x+20-(2(x-16))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We multiply all the terms by the denominator


-((2(x-16)))*2x+20*2x+3=0

Wy multiply elements

-((2(x-16)))*2x+40x+3=0

We add all the numbers together, and all the variables

40x-((2(x-16)))*2x+3=0

We move all terms containing x to the left, all other terms to the right

40x-((2(x-16)))*2x=-3

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