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3/2x+2x=1/2x+3
We move all terms to the left:
3/2x+2x-(1/2x+3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x+3)!=0We add all the numbers together, and all the variables
x∈R
2x+3/2x-(1/2x+3)=0
We get rid of parentheses
2x+3/2x-1/2x-3=0
We multiply all the terms by the denominator
2x*2x-3*2x+3-1=0
We add all the numbers together, and all the variables
2x*2x-3*2x+2=0
Wy multiply elements
4x^2-6x+2=0
a = 4; b = -6; c = +2;
Δ = b2-4ac
Δ = -62-4·4·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*4}=\frac{4}{8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*4}=\frac{8}{8} =1 $
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