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(3/2)*x+5 = 2*x-((1/2)*x)+5 // - 2*x-((1/2)*x)+5
(3/2)*x-(2*x)+(1/2)*x-5+5 = 0
(3/2)*x-2*x+(1/2)*x-5+5 = 0
0 = 0
x naleu017Cy do R
x in (-oo:+oo)
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