If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3/2x+5=69
We move all terms to the left:
3/2x+5-(69)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3/2x-64=0
We multiply all the terms by the denominator
-64*2x+3=0
Wy multiply elements
-128x+3=0
We move all terms containing x to the left, all other terms to the right
-128x=-3
x=-3/-128
x=3/128
| 5x+6-2=4 | | 3-z=13 | | 86=2(1-6k) | | 5w-2=3w+4w | | 48-z=13 | | 3+–w=–1 | | 4(4x+5)=61 | | z=1/16 | | 19=k/2+ 15 | | a^2=-2a+48 | | ,6-5x-2x+10=1x | | 13z=48 | | 48z=3 | | x^2+4x-12x+48=x^2-9x | | 440=8(7-8v) | | -18x=108* | | (X+2)+(5x-2)=2x+5 | | X+x^2=7.5 | | 4a^2+2a=26 | | 12*5=6x | | x^2-21=465 | | -3f+10=-f+8 | | 48z-13=3 | | 7.5*4.5=5x | | d=-9-2d | | 25×t=12.5 | | 48-13z=3 | | -5h-6=-6h-9 | | x-8/12=-11/12 | | 4j-9=-2j-7+8j | | 150=0.8r | | 2-8n+6n=4 |