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3/2x+5x=950
We move all terms to the left:
3/2x+5x-(950)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5x+3/2x-950=0
We multiply all the terms by the denominator
5x*2x-950*2x+3=0
Wy multiply elements
10x^2-1900x+3=0
a = 10; b = -1900; c = +3;
Δ = b2-4ac
Δ = -19002-4·10·3
Δ = 3609880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3609880}=\sqrt{4*902470}=\sqrt{4}*\sqrt{902470}=2\sqrt{902470}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1900)-2\sqrt{902470}}{2*10}=\frac{1900-2\sqrt{902470}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1900)+2\sqrt{902470}}{2*10}=\frac{1900+2\sqrt{902470}}{20} $
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