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3/2x+9/4x+3/20=12/5
We move all terms to the left:
3/2x+9/4x+3/20-(12/5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3/2x+9/4x+3/20-(+12/5)=0
We get rid of parentheses
3/2x+9/4x+3/20-12/5=0
We calculate fractions
(-7680x^2)/1600x^2+480x^2/1600x^2+2400x/1600x^2+3600x/1600x^2=0
We multiply all the terms by the denominator
(-7680x^2)+480x^2+2400x+3600x=0
We add all the numbers together, and all the variables
480x^2+(-7680x^2)+6000x=0
We get rid of parentheses
480x^2-7680x^2+6000x=0
We add all the numbers together, and all the variables
-7200x^2+6000x=0
a = -7200; b = 6000; c = 0;
Δ = b2-4ac
Δ = 60002-4·(-7200)·0
Δ = 36000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36000000}=6000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6000)-6000}{2*-7200}=\frac{-12000}{-14400} =5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6000)+6000}{2*-7200}=\frac{0}{-14400} =0 $
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