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3/2x+9/8x=14
We move all terms to the left:
3/2x+9/8x-(14)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
24x/16x^2+18x/16x^2-14=0
We multiply all the terms by the denominator
24x+18x-14*16x^2=0
We add all the numbers together, and all the variables
42x-14*16x^2=0
Wy multiply elements
-224x^2+42x=0
a = -224; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-224)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-224}=\frac{-84}{-448} =3/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-224}=\frac{0}{-448} =0 $
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