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3/2x-1+2x=-6
We move all terms to the left:
3/2x-1+2x-(-6)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+3/2x+5=0
We multiply all the terms by the denominator
2x*2x+5*2x+3=0
Wy multiply elements
4x^2+10x+3=0
a = 4; b = 10; c = +3;
Δ = b2-4ac
Δ = 102-4·4·3
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{13}}{2*4}=\frac{-10-2\sqrt{13}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{13}}{2*4}=\frac{-10+2\sqrt{13}}{8} $
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