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3/2x-12=x
We move all terms to the left:
3/2x-12-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+3/2x-12=0
We multiply all the terms by the denominator
-1x*2x-12*2x+3=0
Wy multiply elements
-2x^2-24x+3=0
a = -2; b = -24; c = +3;
Δ = b2-4ac
Δ = -242-4·(-2)·3
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-10\sqrt{6}}{2*-2}=\frac{24-10\sqrt{6}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+10\sqrt{6}}{2*-2}=\frac{24+10\sqrt{6}}{-4} $
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