3/2x-7=5/3x+1

Solution for 3/2x-7=5/3x+1 equation:

3/2x-7=5/3x+1

We move all terms to the left:

3/2x-7-(5/3x+1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x+1)!=0

x∈R


We get rid of parentheses

3/2x-5/3x-1-7=0

We calculate fractions


9x/6x^2+(-10x)/6x^2-1-7=0

We add all the numbers together, and all the variables

9x/6x^2+(-10x)/6x^2-8=0

We multiply all the terms by the denominator


9x+(-10x)-8*6x^2=0

Wy multiply elements

-48x^2+9x+(-10x)=0

We get rid of parentheses

-48x^2+9x-10x=0

We add all the numbers together, and all the variables

-48x^2-1x=0

a = -48; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-48)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-48}=\frac{0}{-96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-48}=\frac{2}{-96}
=-1/48
$