3/2y+1/2(y-4)=6

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Solution for 3/2y+1/2(y-4)=6 equation: 



3/2y+1/2(y-4)=6

We move all terms to the left:

3/2y+1/2(y-4)-(6)=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R





Domain of the equation: 2(y-4)!=0

y∈R



We calculate fractions


(6yy/(4y^2y+2y/(4y^2y-6=0

We can not solve this equation

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