3/2y+11=-1/3y+7

Solution for 3/2y+11=-1/3y+7 equation:

3/2y+11=-1/3y+7

We move all terms to the left:

3/2y+11-(-1/3y+7)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 3y+7)!=0

y∈R


We get rid of parentheses

3/2y+1/3y-7+11=0

We calculate fractions


9y/6y^2+2y/6y^2-7+11=0

We add all the numbers together, and all the variables

9y/6y^2+2y/6y^2+4=0

We multiply all the terms by the denominator


9y+2y+4*6y^2=0

We add all the numbers together, and all the variables

11y+4*6y^2=0

Wy multiply elements

24y^2+11y=0

a = 24; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·24·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*24}=\frac{-22}{48}
=-11/24
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*24}=\frac{0}{48}
=0
$