3/2y+6=(20-y)/2

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Solution for 3/2y+6=(20-y)/2 equation:



3/2y+6=(20-y)/2
We move all terms to the left:
3/2y+6-((20-y)/2)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
We add all the numbers together, and all the variables
3/2y-((-1y+20)/2)+6=0
We calculate fractions
()/4y^2+(-((-1y+20)*2y)/4y^2+6=0
We calculate fractions
We do not support eypression: y^4

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