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3/2y-y=4-1/2y
We move all terms to the left:
3/2y-y-(4-1/2y)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 2y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
3/2y-y-(-1/2y+4)=0
We add all the numbers together, and all the variables
-1y+3/2y-(-1/2y+4)=0
We get rid of parentheses
-1y+3/2y+1/2y-4=0
We multiply all the terms by the denominator
-1y*2y-4*2y+3+1=0
We add all the numbers together, and all the variables
-1y*2y-4*2y+4=0
Wy multiply elements
-2y^2-8y+4=0
a = -2; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·(-2)·4
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{6}}{2*-2}=\frac{8-4\sqrt{6}}{-4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{6}}{2*-2}=\frac{8+4\sqrt{6}}{-4} $
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