3/2y=16/y+2

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Solution for 3/2y=16/y+2 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3/2)*y = 16/y+2 // - 16/y+2

(3/2)*y-(16/y)-2 = 0

(3/2)*y-16*y^-1-2 = 0

3/2*y^1-16*y^-1-2*y^0 = 0

(3/2*y^2-2*y^1-16*y^0)/(y^1) = 0 // * y^2

y^1*(3/2*y^2-2*y^1-16*y^0) = 0

y^1

(3/2)*y^2-2*y-16 = 0

(3/2)*y^2-2*y-16 = 0

DELTA = (-2)^2-(-16*4*(3/2))

DELTA = 100

DELTA > 0

y = (100^(1/2)+2)/(2*(3/2)) or y = (2-100^(1/2))/(2*(3/2))

y = 4 or y = -8/3

y in { -8/3, 4}

y in { -8/3, 4 }

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