3/3b-6=7/7b+2

Solution for 3/3b-6=7/7b+2 equation:

3/3b-6=7/7b+2

We move all terms to the left:

3/3b-6-(7/7b+2)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



Domain of the equation: 7b+2)!=0

b∈R


We get rid of parentheses

3/3b-7/7b-2-6=0

We calculate fractions


21b/21b^2+(-21b)/21b^2-2-6=0

We add all the numbers together, and all the variables

21b/21b^2+(-21b)/21b^2-8=0

We multiply all the terms by the denominator


21b+(-21b)-8*21b^2=0

Wy multiply elements

-168b^2+21b+(-21b)=0

We get rid of parentheses

-168b^2+21b-21b=0

We add all the numbers together, and all the variables

-168b^2=0

a = -168; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-168)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-336}=0$