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3/3x-2=5/x-1
We move all terms to the left:
3/3x-2-(5/x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x-1)!=0We get rid of parentheses
x∈R
3/3x-5/x+1-2=0
We calculate fractions
3x/3x^2+(-15x)/3x^2+1-2=0
We add all the numbers together, and all the variables
3x/3x^2+(-15x)/3x^2-1=0
We multiply all the terms by the denominator
3x+(-15x)-1*3x^2=0
Wy multiply elements
-3x^2+3x+(-15x)=0
We get rid of parentheses
-3x^2+3x-15x=0
We add all the numbers together, and all the variables
-3x^2-12x=0
a = -3; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-3)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-3}=\frac{0}{-6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-3}=\frac{24}{-6} =-4 $
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