3/3y=y/2y

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Solution for 3/3y=y/2y equation: 


y in (-oo:+oo)

(3/3)*y = (y/2)*y // - (y/2)*y

(3/3)*y-((y/2)*y) = 0

(-1/2)*y^2+(3/3)*y = 0

y-1/2*y^2 = 0

DELTA = 1^2-(-1/2*0*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)-1)/(-1/2*2) or y = (-1^(1/2)-1)/(-1/2*2)

y = 0 or y = 2

y in { 0, 2 }

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