3/4(-5x-8)=-6(x+4)+1/4

Solution for 3/4(-5x-8)=-6(x+4)+1/4 equation:

3/4(-5x-8)=-6(x+4)+1/4

We move all terms to the left:

3/4(-5x-8)-(-6(x+4)+1/4)=0


Domain of the equation: 4(-5x-8)!=0

x∈R


We calculate fractions


()/(-20x)+(-(-6x+4x0)/(-20x)=0


We calculate terms in parentheses: +(-(-6x+4x0)/(-20x), so:

-(-6x+4x0)/(-20x

We add all the numbers together, and all the variables

-(-2x)/(-20x

We multiply all the terms by the denominator


-(-2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)


We add all the numbers together, and all the variables

2x+()/(-20x)=0

We multiply all the terms by the denominator


2x*(-20x)+()=0

We add all the numbers together, and all the variables

2x*(-20x)=0

We multiply parentheses

-40x^2=0

a = -40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-40)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-80}=0$