3/4(12b-9)+b/4=5-3(2-3b)

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Solution for 3/4(12b-9)+b/4=5-3(2-3b) equation: 



3/4(12b-9)+b/4=5-3(2-3b)

We move all terms to the left:

3/4(12b-9)+b/4-(5-3(2-3b))=0



Domain of the equation: 4(12b-9)!=0

b∈R



We add all the numbers together, and all the variables

3/4(12b-9)+b/4-(5-3(-3b+2))=0

We calculate fractions


-(5-3(-3b+2))=0



We calculate terms in parentheses: -(5-3(-3b+2)), so:

5-3(-3b+2)

determiningTheFunctionDomain
-3(-3b+2)+5

We multiply parentheses

9b-6+5

We add all the numbers together, and all the variables

9b-1

Back to the equation:

-(9b-1)



We get rid of parentheses

-9b+1=0

We move all terms containing b to the left, all other terms to the right

-9b=-1

b=-1/-9

b=1/9

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