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3/4(12m+8)=2/3(6m+9)
We move all terms to the left:
3/4(12m+8)-(2/3(6m+9))=0
Domain of the equation: 4(12m+8)!=0
m∈R
Domain of the equation: 3(6m+9))!=0We calculate fractions
m∈R
(9m6/(4(12m+8)*3(6m+9)))+(-8m1/(4(12m+8)*3(6m+9)))=0
We calculate terms in parentheses: +(9m6/(4(12m+8)*3(6m+9))), so:
9m6/(4(12m+8)*3(6m+9))
We multiply all the terms by the denominator
9m6
We add all the numbers together, and all the variables
9m^6
We do not support empression: m^6
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