3/4(12v-8)=-2/3(6-9v)

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Solution for 3/4(12v-8)=-2/3(6-9v) equation: 



3/4(12v-8)=-2/3(6-9v)

We move all terms to the left:

3/4(12v-8)-(-2/3(6-9v))=0



Domain of the equation: 4(12v-8)!=0

v∈R





Domain of the equation: 3(6-9v))!=0

v∈R



We add all the numbers together, and all the variables

3/4(12v-8)-(-2/3(-9v+6))=0

We calculate fractions


(9v(-)/(4(12v-8)*3(-9v+6)))+(-(-8v1)/(4(12v-8)*3(-9v+6)))=0



We calculate terms in parentheses: +(9v(-)/(4(12v-8)*3(-9v+6))), so:

9v(-)/(4(12v-8)*3(-9v+6))

We add all the numbers together, and all the variables

9v0/(4(12v-8)*3(-9v+6))

We multiply all the terms by the denominator


9v0

We add all the numbers together, and all the variables

9v

Back to the equation:

+(9v)





We calculate terms in parentheses: +(-(-8v1)/(4(12v-8)*3(-9v+6))), so:

-(-8v1)/(4(12v-8)*3(-9v+6))

We add all the numbers together, and all the variables

-(-8v)/(4(12v-8)*3(-9v+6))

We multiply all the terms by the denominator


-(-8v)

We get rid of parentheses

8v

Back to the equation:

+(8v)



We add all the numbers together, and all the variables

17v=0

v=0/17

v=0

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