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3/4(12v-8)=-2/3(6-9v)
We move all terms to the left:
3/4(12v-8)-(-2/3(6-9v))=0
Domain of the equation: 4(12v-8)!=0
v∈R
Domain of the equation: 3(6-9v))!=0We add all the numbers together, and all the variables
v∈R
3/4(12v-8)-(-2/3(-9v+6))=0
We calculate fractions
(9v(-)/(4(12v-8)*3(-9v+6)))+(-(-8v1)/(4(12v-8)*3(-9v+6)))=0
We calculate terms in parentheses: +(9v(-)/(4(12v-8)*3(-9v+6))), so:
9v(-)/(4(12v-8)*3(-9v+6))
We add all the numbers together, and all the variables
9v0/(4(12v-8)*3(-9v+6))
We multiply all the terms by the denominator
9v0
We add all the numbers together, and all the variables
9v
Back to the equation:
+(9v)
We calculate terms in parentheses: +(-(-8v1)/(4(12v-8)*3(-9v+6))), so:We add all the numbers together, and all the variables
-(-8v1)/(4(12v-8)*3(-9v+6))
We add all the numbers together, and all the variables
-(-8v)/(4(12v-8)*3(-9v+6))
We multiply all the terms by the denominator
-(-8v)
We get rid of parentheses
8v
Back to the equation:
+(8v)
17v=0
v=0/17
v=0
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