3/4(12x+100)=57

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Solution for 3/4(12x+100)=57 equation: 



3/4(12x+100)=57

We move all terms to the left:

3/4(12x+100)-(57)=0



Domain of the equation: 4(12x+100)!=0

x∈R



We multiply all the terms by the denominator


-57*4(12x+100)+3=0

Wy multiply elements

-228x(1+3=0

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