3/4(12x+20)=2(3x+6

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Solution for 3/4(12x+20)=2(3x+6 equation: 



3/4(12x+20)=2(3x+6

We move all terms to the left:

3/4(12x+20)-(2(3x+6)=0



Domain of the equation: 4(12x+20)!=0

x∈R



We multiply all the terms by the denominator


-((2(3x+6))*4(12x+20)+3=0

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