3/4(12x+20)=6x+12

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Solution for 3/4(12x+20)=6x+12 equation:



3/4(12x+20)=6x+12
We move all terms to the left:
3/4(12x+20)-(6x+12)=0
Domain of the equation: 4(12x+20)!=0
x∈R
We get rid of parentheses
3/4(12x+20)-6x-12=0
We multiply all the terms by the denominator
-6x*4(12x+20)-12*4(12x+20)+3=0
Wy multiply elements
-24x^2(1-48x(1+3=0

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