3/4(12x+20)=6x+12

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Solution for 3/4(12x+20)=6x+12 equation: 



3/4(12x+20)=6x+12

We move all terms to the left:

3/4(12x+20)-(6x+12)=0



Domain of the equation: 4(12x+20)!=0

x∈R



We get rid of parentheses

3/4(12x+20)-6x-12=0

We multiply all the terms by the denominator


-6x*4(12x+20)-12*4(12x+20)+3=0

Wy multiply elements

-24x^2(1-48x(1+3=0

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