3/4(12x+4)=x+2(x+1)

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Solution for 3/4(12x+4)=x+2(x+1) equation:



3/4(12x+4)=x+2(x+1)
We move all terms to the left:
3/4(12x+4)-(x+2(x+1))=0
Domain of the equation: 4(12x+4)!=0
x∈R
We multiply all the terms by the denominator
-((x+2(x+1)))*4(12x+4)+3=0
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4
We calculate terms in parentheses: -((x+2(x+1)))*4(12x+4), so:
(x+2(x+1)))*4(12x+4

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