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3/4(12x+8)=2/3(x+9)
We move all terms to the left:
3/4(12x+8)-(2/3(x+9))=0
Domain of the equation: 4(12x+8)!=0
x∈R
Domain of the equation: 3(x+9))!=0We calculate fractions
x∈R
(9xx/(4(12x+8)*3(x+9)))+(-8x1/(4(12x+8)*3(x+9)))=0
We calculate terms in parentheses: +(9xx/(4(12x+8)*3(x+9))), so:
9xx/(4(12x+8)*3(x+9))
We multiply all the terms by the denominator
9xx
Back to the equation:
+(9xx)
We calculate terms in parentheses: +(-8x1/(4(12x+8)*3(x+9))), so:We get rid of parentheses
-8x1/(4(12x+8)*3(x+9))
We multiply all the terms by the denominator
-8x1
We add all the numbers together, and all the variables
-8x
Back to the equation:
+(-8x)
9xx-8x=0
We add all the numbers together, and all the variables
-8x+9xx=0
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