3/4(12x-9)+7/4=5-3(2-3x)

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Solution for 3/4(12x-9)+7/4=5-3(2-3x) equation: 



3/4(12x-9)+7/4=5-3(2-3x)

We move all terms to the left:

3/4(12x-9)+7/4-(5-3(2-3x))=0



Domain of the equation: 4(12x-9)!=0

x∈R



We add all the numbers together, and all the variables

3/4(12x-9)-(5-3(-3x+2))+7/4=0

We calculate fractions


-(5-3(-3x+2))=0



We calculate terms in parentheses: -(5-3(-3x+2)), so:

5-3(-3x+2)

determiningTheFunctionDomain
-3(-3x+2)+5

We multiply parentheses

9x-6+5

We add all the numbers together, and all the variables

9x-1

Back to the equation:

-(9x-1)



We get rid of parentheses

-9x+1=0

We move all terms containing x to the left, all other terms to the right

-9x=-1

x=-1/-9

x=1/9

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