3/4(12z-40)=11

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Solution for 3/4(12z-40)=11 equation: 



3/4(12z-40)=11

We move all terms to the left:

3/4(12z-40)-(11)=0



Domain of the equation: 4(12z-40)!=0

z∈R



We multiply all the terms by the denominator


-11*4(12z-40)+3=0

Wy multiply elements

-44z(1+3=0

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