3/4(16x+20)-7=9x-13

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Solution for 3/4(16x+20)-7=9x-13 equation: 



3/4(16x+20)-7=9x-13

We move all terms to the left:

3/4(16x+20)-7-(9x-13)=0



Domain of the equation: 4(16x+20)!=0

x∈R



We get rid of parentheses

3/4(16x+20)-9x+13-7=0

We multiply all the terms by the denominator


-9x*4(16x+20)+13*4(16x+20)-7*4(16x+20)+3=0

Wy multiply elements

-36x^2(1+52x(1-28x(1+3=0

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