3/4(2-3x)=1/3(10x+1)

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Solution for 3/4(2-3x)=1/3(10x+1) equation: 



3/4(2-3x)=1/3(10x+1)

We move all terms to the left:

3/4(2-3x)-(1/3(10x+1))=0



Domain of the equation: 4(2-3x)!=0

x∈R





Domain of the equation: 3(10x+1))!=0

x∈R



We add all the numbers together, and all the variables

3/4(-3x+2)-(1/3(10x+1))=0

We calculate fractions


(9x1/(4(-3x+2)*3(10x+1)))+(-4x0/(4(-3x+2)*3(10x+1)))=0



We calculate terms in parentheses: +(9x1/(4(-3x+2)*3(10x+1))), so:

9x1/(4(-3x+2)*3(10x+1))

We multiply all the terms by the denominator


9x1

We add all the numbers together, and all the variables

9x

Back to the equation:

+(9x)





We calculate terms in parentheses: +(-4x0/(4(-3x+2)*3(10x+1))), so:

-4x0/(4(-3x+2)*3(10x+1))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

9x-4x=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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