3/4(21c-4)=15c+15

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Solution for 3/4(21c-4)=15c+15 equation: 



3/4(21c-4)=15c+15

We move all terms to the left:

3/4(21c-4)-(15c+15)=0



Domain of the equation: 4(21c-4)!=0

c∈R



We get rid of parentheses

3/4(21c-4)-15c-15=0

We multiply all the terms by the denominator


-15c*4(21c-4)-15*4(21c-4)+3=0

Wy multiply elements

-60c^2(2-60c(2+3=0

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