3/4(24-8b)=2(13b+1)

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Solution for 3/4(24-8b)=2(13b+1) equation:



3/4(24-8b)=2(13b+1)
We move all terms to the left:
3/4(24-8b)-(2(13b+1))=0
Domain of the equation: 4(24-8b)!=0
b∈R
We add all the numbers together, and all the variables
3/4(-8b+24)-(2(13b+1))=0
We multiply all the terms by the denominator
-((2(13b+1)))*4(-8b+24)+3=0
We calculate terms in parentheses: -((2(13b+1)))*4(-8b+24), so:
(2(13b+1)))*4(-8b+24
We add all the numbers together, and all the variables
-8b+(2(13b+1)))*4(+24
Back to the equation:
-(-8b+(2(13b+1)))*4(+24)
We add all the numbers together, and all the variables
-(-8b+(2(13b+1)))*424+3=0
We move all terms containing b to the left, all other terms to the right
-(-8b+(2(13b+1)))*424=-3

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