3/4(24-8z)-16=-2/3(9z-12)

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Solution for 3/4(24-8z)-16=-2/3(9z-12) equation: 


z in (-oo:+oo)

(3/4)*(24-(8*z))-16 = (-2/3)*(9*z-12) // - (-2/3)*(9*z-12)

(3/4)*(24-(8*z))-((-2/3)*(9*z-12))-16 = 0

(3/4)*(24-8*z)+(2/3)*(9*z-12)-16 = 0

3/4*(24-8*z)+2/3*(9*z-12)-16 = 0

3/4*(24-8*z)+2/3*(9*z-12)-16 = 0

10-16 = 0

-6 = 0

-6 = 0

z belongs to the empty set

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