3/4(2a-6)+1/2=2/5(3a+20)=

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Solution for 3/4(2a-6)+1/2=2/5(3a+20)= equation: 



3/4(2a-6)+1/2=2/5(3a+20)=

We move all terms to the left:

3/4(2a-6)+1/2-(2/5(3a+20))=0



Domain of the equation: 4(2a-6)!=0

a∈R





Domain of the equation: 5(3a+20))!=0

a∈R



We calculate fractions


(30a3/(4(2a-6)*5(3a+20))*2)+(-(2*4(2a-6)*2)/(4(2a-6)*5(3a+20))*2)+(20a^22/(4(2a-6)*5(3a+20))*2)=0



We calculate terms in parentheses: +(30a3/(4(2a-6)*5(3a+20))*2), so:

30a3/(4(2a-6)*5(3a+20))*2

We multiply all the terms by the denominator


30a3

We add all the numbers together, and all the variables

30a^3

We do not support eapression: a^3

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