3/4(2a-6)-1/2=2/5(3a+20)

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Solution for 3/4(2a-6)-1/2=2/5(3a+20) equation: 



3/4(2a-6)-1/2=2/5(3a+20)

We move all terms to the left:

3/4(2a-6)-1/2-(2/5(3a+20))=0



Domain of the equation: 4(2a-6)!=0

a∈R





Domain of the equation: 5(3a+20))!=0

a∈R



We calculate fractions


(-20a^22/(4(2a-6)*5(3a+20))*2)+(30a3/(4(2a-6)*5(3a+20))*2)+(-(2*4(2a-6)*2)/(4(2a-6)*5(3a+20))*2)=0



We calculate terms in parentheses: +(-20a^22/(4(2a-6)*5(3a+20))*2), so:

-20a^22/(4(2a-6)*5(3a+20))*2

We do not support eapression: a^22

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