3/4(2d-3)=3(d+2)-1/4d

Solution for 3/4(2d-3)=3(d+2)-1/4d equation:

3/4(2d-3)=3(d+2)-1/4d

We move all terms to the left:

3/4(2d-3)-(3(d+2)-1/4d)=0


Domain of the equation: 4(2d-3)!=0

d∈R



Domain of the equation: 4d)!=0

d!=0/1

d!=0

d∈R


We calculate fractions


12d/(-48d^2+8d)+(-(3d-4d2)/(-48d^2+8d)=0


We calculate terms in parentheses: +(-(3d-4d2)/(-48d^2+8d), so:

-(3d-4d2)/(-48d^2+8d

We add all the numbers together, and all the variables

-(+3d-4d^2)/(-48d^2+8d

We multiply all the terms by the denominator


-(+3d-4d^2)

We get rid of parentheses

4d^2-3d

Back to the equation:

+(4d^2-3d)


We get rid of parentheses

12d/(-48d^2+8d)+4d^2-3d=0

We multiply all the terms by the denominator


4d^2*(-48d^2+8d)-3d*(-48d^2+8d)+12d=0

We multiply parentheses

4d^2*(-48d^2+8d)+144d^3-24d^2+12d=0

We do not support edpression: d^3