3/4(2m-5)=2(3m-4)-5/8m

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Solution for 3/4(2m-5)=2(3m-4)-5/8m equation: 



3/4(2m-5)=2(3m-4)-5/8m

We move all terms to the left:

3/4(2m-5)-(2(3m-4)-5/8m)=0



Domain of the equation: 4(2m-5)!=0

m∈R





Domain of the equation: 8m)!=0

m!=0/1

m!=0

m∈R



We calculate fractions


24m/(-160m^2+8m)+(-(6m-20m2)/(-160m^2+8m)=0



We calculate terms in parentheses: +(-(6m-20m2)/(-160m^2+8m), so:

-(6m-20m2)/(-160m^2+8m

We add all the numbers together, and all the variables

-(+6m-20m^2)/(-160m^2+8m

We multiply all the terms by the denominator


-(+6m-20m^2)

We get rid of parentheses

20m^2-6m

Back to the equation:

+(20m^2-6m)



We get rid of parentheses

24m/(-160m^2+8m)+20m^2-6m=0

We multiply all the terms by the denominator


20m^2*(-160m^2+8m)-6m*(-160m^2+8m)+24m=0

We multiply parentheses

20m^2*(-160m^2+8m)+960m^3-48m^2+24m=0

We do not support empression: m^3

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