3/4(2n-3)=6/5(3n+1)

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Solution for 3/4(2n-3)=6/5(3n+1) equation: 



3/4(2n-3)=6/5(3n+1)

We move all terms to the left:

3/4(2n-3)-(6/5(3n+1))=0



Domain of the equation: 4(2n-3)!=0

n∈R





Domain of the equation: 5(3n+1))!=0

n∈R



We calculate fractions


(15n3/(4(2n-3)*5(3n+1)))+(-24n2/(4(2n-3)*5(3n+1)))=0



We calculate terms in parentheses: +(15n3/(4(2n-3)*5(3n+1))), so:

15n3/(4(2n-3)*5(3n+1))

We multiply all the terms by the denominator


15n3

We add all the numbers together, and all the variables

15n^3

We do not support enpression: n^3

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