3/4(2x+1)=1/6(9x-2)

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Solution for 3/4(2x+1)=1/6(9x-2) equation: 



3/4(2x+1)=1/6(9x-2)

We move all terms to the left:

3/4(2x+1)-(1/6(9x-2))=0



Domain of the equation: 4(2x+1)!=0

x∈R





Domain of the equation: 6(9x-2))!=0

x∈R



We calculate fractions


(18x9/(4(2x+1)*6(9x-2)))+(-4x2/(4(2x+1)*6(9x-2)))=0



We calculate terms in parentheses: +(18x9/(4(2x+1)*6(9x-2))), so:

18x9/(4(2x+1)*6(9x-2))

We multiply all the terms by the denominator


18x9

We add all the numbers together, and all the variables

18x^9

We do not support expression: x^9

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