3/4(2x+1)=3/4x

Solution for 3/4(2x+1)=3/4x equation:

3/4(2x+1)=3/4x

We move all terms to the left:

3/4(2x+1)-(3/4x)=0


Domain of the equation: 4(2x+1)!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4(2x+1)-(+3/4x)=0

We get rid of parentheses

3/4(2x+1)-3/4x=0

We calculate fractions


12x/(32x^2+16x)+(-12x2/(32x^2+16x)=0


We calculate terms in parentheses: +(-12x2/(32x^2+16x), so:

-12x2/(32x^2+16x

We multiply all the terms by the denominator


-12x2

We add all the numbers together, and all the variables

-12x^2

Back to the equation:

+(-12x^2)


We get rid of parentheses

-12x^2+12x/(32x^2+16x)=0

We multiply all the terms by the denominator


-12x^2*(32x^2+16x)+12x=0