3/4(2x+4)=x+19)

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Solution for 3/4(2x+4)=x+19) equation: 



3/4(2x+4)=x+19)

We move all terms to the left:

3/4(2x+4)-(x+19))=0



Domain of the equation: 4(2x+4)!=0

x∈R



We get rid of parentheses

3/4(2x+4)-x-19)=0

We multiply all the terms by the denominator


-x*4(2x+4)-19)*4(2x+3+4)=0

We add all the numbers together, and all the variables

-x*4(2x+4)-19)*4(2x+7)=0

We add all the numbers together, and all the variables

-x*4(2x+4)-19)*4(2x=0

Wy multiply elements

-4x^2(2-19)*4(2x=0

We add all the numbers together, and all the variables

-4x^2(-17)*4(2x=0

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